画像をダウンロード y(xy 2x^2y^2)dx x(xy-x^2y^2)dy=0 341343

How To Solve Math X Y 2 Dx 2xy Dy 0 Quora

How To Solve Math X Y 2 Dx 2xy Dy 0 Quora

See the answer See the answer See the answer done loading solve the DE (x^2yxyy)dx (x^2y2x^2)dy=0 the solution should be xlnxx^1y2lny=c Best Answer This is the best answer based on feedback and ratingsQuestion Solve the differential equation (xy^2 y^2 x 1)dx (x^2y 2xy 2xy x^2 2y 2x 2)dy = 0 This problem has been solved!

Y(xy 2x^2y^2)dx x(xy-x^2y^2)dy=0

Y(xy 2x^2y^2)dx x(xy-x^2y^2)dy=0-(y^2)dx (x^2 xy y^2)dy = 0 Natural Language; $$ (y^2 2x^2y)dx (2x^3 xy)dy = 0 $$ I tried to solve the differential equation in the following manner, but I am unable to arrive at the correct solution The correct solution is

Solve Xy Cos Xy Sin Xy Dx X 2cos Xy Dy 0 Youtube

Solve Xy Cos Xy Sin Xy Dx X 2cos Xy Dy 0 Youtube

 The solution of the differential equation `y (xy 2x^2y^2) dx x (xyx^2y^2)dy = 0`, is given y ( y 2 x 2) ( 2 x d x) 2 x 2 ( 2 x 2 − y) d y = 0 An obvious change of variable appears t = x 2 d t = 2 x d x y ( y 2 t) d t 2 t ( 2 t − y) d y = 0 d y d t = y 2 t y 2 t y − 2 t This is an ODE of the homogeneous kind The usual change of function is y = t uAnswer (1 of 4) (x^2y^2)dx(x^2 xy)dy=0 \implies \dfrac{dy}{dx}= \dfrac{x^2 y^2}{x^2xy} Dividing Numerator and Denominator by 'x^2′, \implies \dfrac{dy}{dx

SolutionGiven , Differential Equation is(x 2−yx 2)dy(y 2xy 2)dx=0This can be Simplified as(yx 2−x 2)dy=(y 2xy 2)dxx 2(y−1)dy=y 2(1x)dxy 2dy(y−1)= x 2dx(1x)Now On Integrating both side , we get∫ y 2dy(y−1)=∫ x 2dx(1x)∫y1− y 21dy=∫x1 x 21dx∫ ydy− y 2dy=∫ xdx x 2dxln∣y∣− y1=ln∣x∣− x1lnCln∣y∣−ln∣x∣−lnC= y1− x1lnc∣x∣∣y∣= xyx−y A curve satisfies the differential equation `(dy)/(dx)=(x1xy^2)/(x^2yy)` and passes through `(0,0)` (1) The equation of the curve is `x^2y^22x=x^ asked in Differential Equations by Gaurangi ( 250k points)The given Equation is not an exact differential equation M and N are homogenous functions of degree 3 I F = 1 M x N y = 1 ( x 2 y − 2 x y 2) x − ( x 3 − 3 x 2 y) y = 1 ( x 3 y − 2 x 2 y 2) − ( x 3 y − 3 x 2 y 2) = 1 x 2 y 2 Multiplying the given equation by the integrating factor, we get ( x 2 y = 2 x y 2) 1 x 2 y 2 d x −

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